X^2+14x+33=(x+3)

Solution for X^2+14x+33=(x+3) equation:

X^2+14X+33=(X+3)

We move all terms to the left:

X^2+14X+33-((X+3))=0


We calculate terms in parentheses: -((X+3)), so:

(X+3)

We get rid of parentheses

X+3

Back to the equation:

-(X+3)


We get rid of parentheses

X^2+14X-X-3+33=0

We add all the numbers together, and all the variables

X^2+13X+30=0

a = 1; b = 13; c = +30;
Δ = b2-4ac
Δ = 132-4·1·30
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*1}=\frac{-20}{2}
=-10
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*1}=\frac{-6}{2}
=-3
$